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Find the general solution of the homogeneous differential equation.

The equation is :
$$\frac{d^2y}{dx^2} + \left( \frac {2(1-\cos x)}{\sin x }\right )\frac{dy}{dx} + \lambda y = 0$$
I found out the solution of the homogeneous equation is :
$$y = c_1\cos x + c_2\sin x$$
I found $c_1$ and $c_2$. Am I missing something?
Is there a way to find the general solution to this equation?

A:

Writing the equation as
$$\frac{d^2y}{dx^2} + (1-\cos x)\frac{dy}{dx} + \lambda y = 0$$
We get
$$\frac{d}{dx}\left(\frac{dy}{dx} + (1-\cos x)\frac{dy}{dx} – \lambda y\right) = 0$$
We now use the total different of the preceding equation:
$$\frac{d}{dx}\left(\frac{d}{dx}\left(\frac{dy}{dx} + (1-\cos x)\frac{dy}{dx} – \lambda y\right)\right) = 0$$
We find
$$\frac{d^2y}{dx^2} + (1-\cos x)\frac{d^2y}{dx^2} + 2(1-\cos x)\frac{d}{dx}\frac{dy}{dx} – 2\lambda\frac{dy}{dx} + (1-\cos x)\frac{d}{dx}(\lambda y) = 0$$

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Couldnt find a way to get it to work. It says that my serial number is wrong and I need to install the program. Can anyone help me?Q:

Can I use local Java agent to monitor my JRuby app?

I have a JRuby app that i need to monitor and I’d like to use the local java agent to do that.
So I create this file in my app (Directory) to open a socket and communicate back:
import java.io.IOException;

import org.jruby.evaluator.AbstractInterpreter;
import org.jruby.evaluator.Context;
import org.jruby.evaluator.EvalError;
import org.jruby.evaluator.EvalException;
import org.jruby.javasupport.JavaRubyRunnable;
import org.jruby.javasupport.JavaUtilRunnable;

public class JavaLocalRubyAgent extends JavaUtilRunnable {
public void run() {

Runtime.getRuntime().addShutdownHook(new Thread() {
public void run() {
System.exit(0);
}
});

try {
Context context = new Context();

Socket socket = new Socket(“localhost”, 4444);

context.set(“socket”, socket);

AbstractInterpreter i = new AbstractInterpreter() {
protected void interpret(Context context) throws EvalException {
try {
//DO SOMETHING

} catch (IOException